useArrayJoin
リアクティブな Array.join
使い方
複数の参照を持つ配列での使用
js
import { useArrayJoin } from '@vueuse/core'
const item1 = ref('foo')
const item2 = ref(0)
const item3 = ref({ prop: 'val' })
const list = [item1, item2, item3]
const result = useArrayJoin(list)
// result.value: foo,0,[object Object]
item1.value = 'bar'
// result.value: bar,0,[object Object]
リアクティブな配列での使用
js
import { useArrayJoin } from '@vueuse/core'
const list = ref(['string', 0, { prop: 'val' }, false, [1], [[2]], null, undefined, []])
const result = useArrayJoin(list)
// result.value: string,0,[object Object],false,1,2,,,
list.value.push(true)
// result.value: string,0,[object Object],false,1,2,,,,true
list.value = [null, 'string', undefined]
// result.value: ,string,
リアクティブな区切り文字での使用
js
import { useArrayJoin } from '@vueuse/core'
const list = ref(['string', 0, { prop: 'val' }])
const separator = ref()
const result = useArrayJoin(list, separator)
// result.value: string,0,[object Object]
separator.value = ''
// result.value: string0[object Object]
separator.value = '--'
// result.value: string--0--[object Object]
型定義
typescript
/**
* Reactive `Array.join`
*
* @see https://vueuse.dokyumento.jp/useArrayJoin
* @param list - the array was called upon.
* @param separator - a string to separate each pair of adjacent elements of the array. If omitted, the array elements are separated with a comma (",").
*
* @returns a string with all array elements joined. If arr.length is 0, the empty string is returned.
*/
export declare function useArrayJoin(
list: MaybeRefOrGetter<MaybeRefOrGetter<any>[]>,
separator?: MaybeRefOrGetter<string>,
): ComputedRef<string>
ソース
貢献者
変更履歴
v12.0.0-beta.1
2024/11/21v10.0.0-beta.4
2023/04/134d757
- feat(types)!: MaybeComputedRef
を MaybeRefOrGetter
にリネーム0a72b
- feat(toValue): resolveUnref
を toValue
にリネーム